How To Solve Quadratic Equations: 5 Simple Methods With Examples

Asked 7 months ago
Answer 1
Viewed 103
0

Quadratic equations might seem intimidating at first, but once you understand the different solving methods, they become much easier to handle. Whether you're a Class 10 student or just brushing up on algebra, this guide will walk you through five key methods to solve any quadratic equation, complete with examples.

Quadratic Equation

What Is a Quadratic Equation?

A quadratic equation is a second-degree polynomial in the form:

ax² + bx + c = 0

Where:

a, b, c are real numbers (a ≠ 0).

x represents the variable.

These equations appear in real-world scenarios like calculating projectile motion, optimizing profit in business, or determining dimensions in geometry.

Related: How to crack International Mathematical Olympiad?

5 Methods to Solve Quadratic Equations

1. Factoring Method (Best for simple, factorable equations)

When to use: If the quadratic can be broken into two binomials.

Steps:

Write the equation in standard form: ax² + bx + c = 0.

Find two numbers that:

Multiply to a × c.

Add to b.

Split the middle term and factor by grouping.

Set each factor to zero and solve for x.

Example: Solve x² + 5x + 6 = 0

Numbers: 2 and 3 (since 2 × 3 = 6 and 2 + 3 = 5).

Factored form: (x + 2)(x + 3) = 0

Solutions: x = -2, x = -3

2. Completing the Square (Useful when factoring is difficult)

When to use: For equations that don’t factor easily.

Steps:

Move the constant term (c) to the other side.

Divide all terms by a (if a ≠ 1).

Take half of b, square it, and add to both sides.

Rewrite the left side as a perfect square.

Solve for x.

Example: Solve x² + 6x + 5 = 0

Rewrite: x² + 6x = -5

Complete the square: x² + 6x + 9 = 4 (since (6/2)² = 9)

Perfect square: (x + 3)² = 4

Solutions: x = -1, x = -5

3. Quadratic Formula (Works for any quadratic equation)

The universal method for solving quadratics:

Formula:

Quadratic Formula

Steps:

Identify a, b, c from the equation.

Plug into the formula.

Simplify under the square root (discriminant).

Solve for x.

Example: Solve 2x² + 4x – 6 = 0

a = 2, b = 4, c = -6

Discriminant: √(16 + 48) = √64 = 8

Solutions: x = 1, x = -3

4. Splitting the Middle Term (Alternative to factoring)

When to use: For equations like ax² + bx + c where a ≠ 1.

Steps:

Multiply a × c.

Find two numbers that multiply to a × c and add to b.

Split the middle term and factor.

Example: Solve 6x² + 11x + 4 = 0

a × c = 24 → Numbers: 8 and 3 (8 + 3 = 11)

Rewrite: 6x² + 8x + 3x + 4 = 0

Factor: (2x + 1)(3x + 4) = 0

Solutions: x = -½, x = -4/3

Related: Is computer science the same as software engineering math?

5. Graphical Method (Visual approach for real-world applications)

When to use: To estimate real roots visually.

Steps:

Plot the quadratic function y = ax² + bx + c.

The x-intercepts (where y = 0) are the solutions.

Example: Graph y = x² – 4 → Roots at x = 2, x = -2.

FAQs on Quadratic Equations

Q: Which method is easiest?

A: Factoring (if the equation is simple). Otherwise, the quadratic formula always works.

Q: What if the discriminant is negative?

A: The equation has no real roots (only complex solutions).

Q: How is this useful in real life?

A: Used in physics (projectile motion), engineering (structural design), and finance (profit optimization).

Q: What’s the biggest mistake students make?

A: Forgetting to check all solutions or misapplying the quadratic formula.

Final Tips for Solving Quadratics

✔ Memorize the quadratic formula – it’s a lifesaver!
✔ Practice factoring – it’s faster when it works.
✔ Check your answers by plugging them back into the equation.

Now you’re ready to tackle any quadratic equation! Try solving these:

x² – 9 = 0

2x² + 5x – 3 = 0

Drop your answers in the comments! 

Answered 7 months ago Matti Karttunen